The aluminum rod AB (G=27 GPa) is bonded to the brass rod BD(G=39 GPa). Knowing that portion CD of the brass rod is hollow andhas an inner diameter of 40 mm, determine the angle of twist atA.

This seemed fairly straight forward, but my answer does notmatch the answer in the back of my book (which is6.02^o). Oddly, my answer in radians seems to be off by afactor of 16. I cannot account for this. Help please? I always rateanswers.

Transcribed Image Text:

T(A)=+800 N*m 36 mm I A 400 400 mm T(B)=+1600 N*m B 375 mm C D 1250 mmk Tor 60 mm T(A)=+800 N*m 36 mm I A 400 400 mm T(B)=+1600 N*m B 375 mm C D 1250 mmk Tor 60 mm

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