The average energy $E($in kcal $)$ needed for a lizard to walk or run a distance of $1$ km has been modeled by the equation

$E(m,v)=2\mathrm{.}65m^{0\mathrm{.}66}+\frac{3\mathrm{.}5m^{0\mathrm{.}75}}{v}$

where $m$ is the body mass of the lizard $($in grams$)$ and $v$ is its speed $($in $k\frac{m}{h}).$ Calculate $E_m(405,7)$ and $)$ and interpret your answers.t

$E_m(405,7)=,$kca$\frac{l}{g}($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its weight increases is $m=g$ and $v=,k\frac{m}{h}.$ kilocalories per gram when $E_v(405,7)$~~ $$ kca$\frac{l}{k\frac{m}{h}}($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its speed increase is $k\frac{m}{h}r$ increase in speed, when $m=q,7$ and $v=k\frac{m}{h}.$ kcal of energy for each $1$