The behavior of the gap of the semiconductor alloy Al, Gai E,(x) = 1.42 + 1.087z+0.438x2...

 

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The behavior of the gap of the semiconductor alloy Al, Gai E,(x) = 1.42 + 1.087z+0.438x2 As can be approximated quite well by The gap is direct for <0.43. Calculate a) the alloy to obtain a semiconductor that emits at 780 nm and b) the range of wavelengths that can be covered efficiently (direct gap) for this family of semiconductor alloys. The behavior of the gap of the semiconductor alloy Al, Gai E,(x) = 1.42 + 1.087z+0.438x2 As can be approximated quite well by The gap is direct for <0.43. Calculate a) the alloy to obtain a semiconductor that emits at 780 nm and b) the range of wavelengths that can be covered efficiently (direct gap) for this family of semiconductor alloys.

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