The bioactivity of four different drugs A, B, C, D for treating a particular illness was...

 

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The bioactivity of four different drugs A, B, C, D for treating a particular illness was compared in a study and the following ANOVA table was given for the data: degree of Squares Freedom Squares Source of sum of Mean Variation Treatment 64.42 3 21.47 Residual 62.12 26 2.39 Total 126.54 29 The treatment averages are as follows: JA = 66.17, JB = 65.75, c = 62.63, and 63.85 The sample size for each treatmnet are: nA 7, пв 8, пс 9 and %3D np = 6 (a) Use an F test to test at the 0.01 significant level the null hypothesis that the four treatments have the same bioactivity. Compute the p value of the observed F statistic. (b) Use the pairwise t test to check the difference between all the possible pairs of treatment. (c) Use the Bonferroni method to perform multiple comparisons of the four treatments at the 0.01 level. (d) Use the Tukey method to perform multiple comparisons of the four treatments at the 0.01 level. (e) Compare the results in (b), (c) and (d). The bioactivity of four different drugs A, B, C, D for treating a particular illness was compared in a study and the following ANOVA table was given for the data: degree of Squares Freedom Squares Source of sum of Mean Variation Treatment 64.42 3 21.47 Residual 62.12 26 2.39 Total 126.54 29 The treatment averages are as follows: JA = 66.17, JB = 65.75, c = 62.63, and 63.85 The sample size for each treatmnet are: nA 7, пв 8, пс 9 and %3D np = 6 (a) Use an F test to test at the 0.01 significant level the null hypothesis that the four treatments have the same bioactivity. Compute the p value of the observed F statistic. (b) Use the pairwise t test to check the difference between all the possible pairs of treatment. (c) Use the Bonferroni method to perform multiple comparisons of the four treatments at the 0.01 level. (d) Use the Tukey method to perform multiple comparisons of the four treatments at the 0.01 level. (e) Compare the results in (b), (c) and (d).

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a The hypothesis being tested is Null Hypothesis H 0 1 2 3 4 Alternative Hypothesis H a At least one ... View the full answer