The capacitor has no voltage when the switch is closed at $t=0.$ The switch is opened at $t=1$ secand$.$

Draw graph of $V_c(t)$ for these cases:

a$)C={10}^{-6}F,I={10}^{-3}A$

b$)C={10}^{-6}F,I=5{10}^{-3}A$

c$)C=0\mathrm{.}5{10}^{-6}F,I={10}^{-3}A$