The $*$ circuit depicted in Fig$\mathrm{.}11\mathrm{.}83$ is called an$$active inductor.$$ Neglecting other capacitances and assuming$=0,$ compute Zin. Use Bode$$s rule to plot $|$Zin$|$ as a function of frequency and explain why it exhibits inductive behavior.

Figure $11\mathrm{.}83$