Question: The code is suppose to read all the inputs and spit out the output However it stopped after two Here's the code someone help #include

The code is suppose to read all the inputs and spit out the output 

Example Input: 12/1/2023 500 d 12/11/2023 200 d 12/23/2023 100 c 12/28/2023

However it stopped after two 

200 d 12/31/2023 250 Example Output: 30-day average balance (12/1/2023-12/30/2023): $360.00


Here's the code someone help

#include  #include    using namespace std;   const int MAX_TRANSACTIONS = 100;   struct Transaction {    char type;  // 'd' for debit, 'c' for credit, 'b' for balance    string date;    double value; };   int daysInMonth(int month, int year) {    if (month == 2) {        if ((year % 400 == 0) || ((year % 100 != 0) && (year % 4 == 0)))            return 29; // Leap year        else            return 28;    } else if (month == 4 || month == 6 || month == 9 || month == 11) {        return 30;    } else {        return 31;    } }   int main() {    Transaction transactions[MAX_TRANSACTIONS];    int numTransactions = 0;     // Read the initial balance    double balance;    cin >> transactions[0].date >> balance;    transactions[0].type = 'b';  // 'b' for balance     int startDay, startMonth, startYear;    sscanf(transactions[0].date.c_str(), "%d/%d/%d", &startMonth, &startDay, &startYear);     int currentDay = startDay;    int currentMonth = startMonth;    int currentYear = startYear;     // Read transactions until 'q' or more than 30 days    while (true) {        // Handle overdraft before checking transaction order        if (transactions[numTransactions].type == 'd' && balance > transactions[numTransactions + 1].type;        if (transactions[numTransactions + 1].type == 'q') break;         cin >> transactions[numTransactions + 1].date >> transactions[numTransactions + 1].value;         int transactionDay, transactionMonth, transactionYear;        sscanf(transactions[numTransactions + 1].date.c_str(), "%d/%d/%d",               &transactionMonth, &transactionDay, &transactionYear);         if (transactionYear = 30) {            break;        }    }     // Calculate and print average balance    double averageBalance = balance / (numTransactions + 1);    cout    

Example Input: 12/1/2023 500 d 12/11/2023 200 d 12/23/2023 100 c 12/28/2023 200 d 12/31/2023 250 Example Output: 30-day average balance (12/1/2023-12/30/2023): $360.00

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