The code snippet provided in the image seems to be from an assembly language or a similar low$-$level language, defining an array using the $`$DUP$`$ directive which is used to duplicate items.$($a$)$ The items in the array are created by duplicating the structure defined within the parentheses. Here's the breakdown:$-`2$ DUP$(\text{'}$a$\text{'})`$ means the character $\text{'}$a$\text{'}$ is duplicated twice, so it becomes $\text{'}$a$\text{'},\text{'}$a$\text{'}.-`3$ DUP$(2$ DUP$(\text{'}$a$\text{'}))`$ means the structure $\text{'}$a$\text{'},\text{'}$a$\text{'}$ is duplicated three times.So the items in the array are: $\text{'}$a$\text{'},\text{'}$a$\text{'},\text{'}$a$\text{'},\text{'}$a$\text{'},\text{'}$a$\text{'},\text{'}$a$\text{'}.($b$)$ To calculate the total size of the array in bytes, we need to know the size of each $`$WORD$`.$ In most assembly languages, a $`$WORD$`$ is typically $2$ bytes. There are $3$ structures, each containing $2`$WORD$`$s$,$ so there are $6`$WORD$`$s in total.Total size in bytes $=$ number of WORDs $*$ size of each WORDTotal size in bytes $=6*2$Total size in bytes $=12$ bytesThe array should take up $12$ bytes of memory.