The correct answer is 0.0435r. The colored work proves that my answer of 0.250r is wrong. Please show the correct work step by step to prove the answer of 0.0435r.

Question 7 1 / 1 pts When pressure changes by value of Ap, the change in volume of sphere of side a is AV # 4/3 TT (Ar) 3 AV = --Vo. If the volume is Vo = = mrs, the change in the radius Ar is - 1/8 Vo # 4/3 TT ( Ar) 3 O 0.125r. 4/3 TT (Ar) 3 = 3/4 TTr3 O 0.500r. ( Ar) 3 = 3/4 53 0.0435r. Ar = 13 8/4 53] O 0.06467: Ar = 0.asorX Ar=vg-vi 0.250r. Note: AV = VS- Vi = yari3 - YTTris =- 1 STris = > rout