The current through a branch in a linear network is

$2$ A when the input source voltage is $10$ V$.$ If the volt$-$

age is reduced to $1$ V and the polarity is reversed, the

current through the branch is:

$($a$)2$ A $($b$)0\mathrm{.}2$ A $($c$)0\mathrm{.}2$ A

$($d$)2$ A $($e$)20$ A