The cylindrical hub of length l$2$ can slide along the rod of length l$1.$ A disk of radius R and out$-$of$-$plane thickness t is attached at one end of the rod, as illustrated in Figure $2\mathrm{.}47.$ The hub is relocated from the left end of the rod to the right end, where it becomes tangent to the disk. Calculate the change in the mass moment of inertia of this compound pendulum with respect to an end axis passing through O and perpendicular to the plane of the pendulum. Known are d$1=0\mathrm{.}005$ m$,$ d$2=0\mathrm{.}01$ m$,$ l$1=0\mathrm{.}3$ m$,$ l$2=0\mathrm{.}1$ m$,$ R $=0\mathrm{.}04$ m$,$ t $=0\mathrm{.}005$ m$,$ and the mass density of all parts forming the pendulum, $\backslash$rho $=6800$ kg$/$m$3.$