Question: The differentiation and integration properties can be used to transform circuits involving capacitive and inductive elements. The circuits may be solved directly in terms of

 The differentiation and integration properties can be used to transform circuits

The differentiation and integration properties can be used to transform circuits involving capacitive and inductive elements. The circuits may be solved directly in terms of Laplace transform, rather than by first writing the differential equation in the time domain. This is accomplished by replacing resistive, capacitive and inductive elements by their Laplace transform equivalents. A resistance R with corresponding Va(t) and current i, (t) satisfies the relation VR(t) = Ria(t). Transforming the equation to Laplace transform, get VR(s) = RIR(s). There are FOUR (4) objectives for this assessment as outlined below: 1. to define the relation of the Laplace transform equation for capacitive C and inductive L, 2. to design a series-parallel circuit that contains one component of resistor, capacitor and inductor with input signal x(t) = cos(t)u(t). You can choose your values for the components, 3. to draw the equivalent Laplace transform circuit for the series-parallel circuit in objective number 2, and 4. to analyze the output voltage y(t) across the last component in the circuit

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