The distributed dead load on this beam, wDL$,$ is $\_\_\_\_$ k$/$ft$.$

Flag question: Question $23$

Question $234\mathrm{.}25$ pts

The combined factored distributed load, wfactored, is $\_\_\_$ k$/$ft$.$

$($Note$,$ this is the w you can use in the equation to solve for Mmax $=$ Mdemand$)$

Flag question: Question $24$

Question $244\mathrm{.}25$ pts

The demand moment, Mdemand, is $\_\_\_\_$ k$-$ft$.$

Flag question: Question $25$

Question $254\mathrm{.}25$ pts

Which formula would you use to calculate the depth of the compression block, a$?$

Group of answer choices

Cc $=0\mathrm{.}85$f'cab

Mdemand $=$

$(0\mathrm{.}85$f'cab$)($d$-$a$/2)$

fyAs $=0\mathrm{.}85$f'cab

s$=$

c$(($d$-$c$)/$c$)$

Flag question: Question $26$

Question $264\mathrm{.}25$ pts

The depth of the compression block, a$,$ is $\_\_\_\_$ inches.

Flag question: Question $27$

Question $274\mathrm{.}25$ pts

Which equation would you use to calculate the minimum area of steel, As$,$req'd?

Group of answer choices

Cc $=0\mathrm{.}85$f'cab

T$=$fyAs

fyAs $=0\mathrm{.}85$f'cab

s$=$

c$(($d$-$c$)/$c$)$

Flag question: Question $28$

Question $284\mathrm{.}25$ pts

The minimum area of steel, As$,$req'd, is $\_\_\_\_$ in$2.$

Flag question: Question $29$

Question $294\mathrm{.}25$ pts

Which combination of bars will satisfy that area of steel $($As$,$req'd$)?$

Group of answer choices

One #$11$ bar

Two #$7$ bars

Three #$8$ bars

Four #$6$ bars