The edges of the rectangular plate are kept at the temperatures shown in the figure below...

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The edges of the rectangular plate are kept at the temperatures shown in the figure below T = 0°C 1 T = 0°C 2 3 T = 100°C T= 200°C Assuming steady-state heat conduction, the differential equation governing the temperature T in the interior is: агт агт + Əx² əy² = = 0 If this equation is approximated by finite differences using the mesh shown, we obtain the following algebraic equations for temperatures at the mesh points: 1 -4 1 This is a tridiagonal matrix. Use three iterations of Gauss-Seidel method to solve for the temperature at each node (1, 2, 3). Consider that T₁-T2-T3-10°C as initial values. 0 --L The edges of the rectangular plate are kept at the temperatures shown in the figure below T = 0°C 1 T = 0°C 2 3 T = 100°C T= 200°C Assuming steady-state heat conduction, the differential equation governing the temperature T in the interior is: агт агт + Əx² əy² = = 0 If this equation is approximated by finite differences using the mesh shown, we obtain the following algebraic equations for temperatures at the mesh points: 1 -4 1 This is a tridiagonal matrix. Use three iterations of Gauss-Seidel method to solve for the temperature at each node (1, 2, 3). Consider that T₁-T2-T3-10°C as initial values. 0 --L The edges of the rectangular plate are kept at the temperatures shown in the figure below T = 0°C 1 T = 0°C 2 3 T = 100°C T= 200°C Assuming steady-state heat conduction, the differential equation governing the temperature T in the interior is: агт агт + Əx² əy² = = 0 If this equation is approximated by finite differences using the mesh shown, we obtain the following algebraic equations for temperatures at the mesh points: 1 -4 1 This is a tridiagonal matrix. Use three iterations of Gauss-Seidel method to solve for the temperature at each node (1, 2, 3). Consider that T₁-T2-T3-10°C as initial values. 0 --L The edges of the rectangular plate are kept at the temperatures shown in the figure below T = 0°C 1 T = 0°C 2 3 T = 100°C T= 200°C Assuming steady-state heat conduction, the differential equation governing the temperature T in the interior is: агт агт + Əx² əy² = = 0 If this equation is approximated by finite differences using the mesh shown, we obtain the following algebraic equations for temperatures at the mesh points: 1 -4 1 This is a tridiagonal matrix. Use three iterations of Gauss-Seidel method to solve for the temperature at each node (1, 2, 3). Consider that T₁-T2-T3-10°C as initial values. 0 --L