The equation of the line PQ joining point P(2,-4) and passes through y-axis at y= -5...

 

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The equation of the line PQ joining point P(2,-4) and passes through y-axis at y= -5 can be written in the form y=mx+c. Find m and c. m = C= A second line RS joins R(3,7) and S, its equation is 2y=A+Bx and it is perpendicular to PQ. Find the slope of RS, A and B. What is the y-intercept for line RS? slope of RS = A = B = y-intercept = The equation of the line PQ joining point P(2,-4) and passes through y-axis at y= -5 can be written in the form y=mx+c. Find m and c. m = C= A second line RS joins R(3,7) and S, its equation is 2y=A+Bx and it is perpendicular to PQ. Find the slope of RS, A and B. What is the y-intercept for line RS? slope of RS = A = B = y-intercept =

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Answer 1 Equation of the line PQ Point P is 2 4 and it passes through the yaxis at y 5 To find the e... View the full answer