Question: The expected value is a linear operator, which means that we can pull constants out of the expectation. So, E[2Ycos(t)] = 2cos(t)E[Y]...here why are we

The expected value is a linear operator, which means that we can pull constants out of the expectation. So, E[2Ycos(t)] = 2cos(t)E[Y]...here why are we just doing expected value of Y and not coswt...can u give analogy to explain

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