Question: The exponential model A = 916.60-0221 describes the population, A, of a country in millions, t years after 2003. Use the model to determine the

 The exponential model A = 916.60-0221 describes the population, A, of

The exponential model A = 916.60-0221 describes the population, A, of a country in millions, t years after 2003. Use the model to determine the population of the country in 2003. The population of the country in 2003 was million. 2. The exponential models describe the population of the indicated country, A, in millions, t years after 2006. Which country has the greatest growth rate? By what percentage is the population of that country increasing each year? Country 1: A = 26.70.026t Country 2 A = 126.6 0.005t Country 3: A = 1084.6-0.019t Country 4: A = 149.4e- 0.004t Country has the greatest growth rate . The population of that country is increasing by % each year. (Round to the nearest tenth as needed.) 3. The exponential model A = 879.80.052 describes the population, A, of a country in millions, t years after 2003. Use the model to determine when the population of the country will be 1101 million. The population of the country will be 1101 million in (Round to the nearest year as needed.) Complete the table shown to the right for the population growth model for a certain country. 2003 Population(millions) Projected 2018 Population (millions) Projected Growth Rate, k 102.5 0.0116 The projected 2018 population is million. (Round to one decimal place as needed.) Complete the table shown to the right for the population growth model for a certain country. 2007 Population (millions) Projected 2024 Population (millions) Projected Growth Rate, k 46.9 18.3 K = (Round to four decimal places as needed.) 6. An artifact originally had 16 grams of carbon-14 present. The decay model A = 16e-0-000121 describes the amount of carbon-14 present after t years. Use the model to determine how many grams of carbon-14 will be present in 6983 years. The amount of carbon-14 present in 6983 years will be approximately grams. (Round to the nearest whole number.) 7 . The half-life of the radioactive element unobtanium-47 is 10 seconds. If 176 grams of unobtanium-47 are initially present, how many grams are present after 10 seconds? 20 seconds? 30 seconds? 40 seconds? 50 seconds? The amount left after 10 seconds is grams . The amount left after 20 seconds is grams. The amount left after 30 seconds is grams. The amount left after 40 seconds is grams. The amount left after 50 seconds is grams. (Round to one decimal place.)

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