Question: The figure above shows the graph of the continuous function f. The regions A,B,C,D, and E have areas 5,2,16,5, and 6, respectively. For -7x9, the

The figure above shows the graph of the continuous function f. The regions A,B,C,D, and E have areas 5,2,16,5, and 6, respectively. For -7x9, the function g is defined by g(x)=-6-3xf(t)dt.(a) Is there a value of x, for -3x2, such that g(x)=0? Justify your answer.(b) Find the absolute minimum value of g and the absolute maximum value of g on the interval -7x9. Justify your answer.(c)(i) Find (2x16)dx.(ii) Find the value of -7-5f(2x16)dx.The figure above shows the graph of f', the dervative of a differentiatile function f, an the closed interval 0:T. The areas of the regions between the graph of f' and the x axis are labeled in the figure. The function f is defined for all real numbers and sabifies f(4)=10.Let g be the function defined by g(x)=5-x2.(a) Find the value of 07f'(x)dx.(b) Given that f(4)=10, withe an expression for f(x) that involves an integral. Use this expression to find the absolate mirimam value of fand the absolute maximum value of fon the closed interval 057. Justify pour answers.(c) Find g(x)dx.no

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