The figure below shows a longitudinal section in a channel of wide cross section. Manning's n = 0.02 and the bed slope is 0.001. B A q=Cad 2g(H-Cd) and for a submerged outflow is: A gate is located at point A. The discharge equation for the gate in case of free outflow is given by: So=1/1000, n = = 0.02 q=Cd2g(H - y) Where q is the discharge per unit width (m/sec), Ca is the discharge coefficient and is equal to 0.6, d is the height of the gate opening (m), H is the water depth just upstream of the gate (m), y is the water depth downstream the gate (m), and g is the gravitational acceleration (m/sec). The coefficient of contraction of the gate Cc = 0.63. a) If q = 3 m/sec/m', and H= 3m, find the gate opening d, and check if a free hydraulic jump will form downstream of the gate. Assume the channel downstream A is long enough to allow for uniform flow to develop. If a jump will form, how far downstream of A will it be? (Use an appropriate method to calculate the distance) b) Point B is located 600m upstream of the gate. Find the water depth at B. Use the step by step method considering two steps. If the bed level at A = 20.75m, find the water level at B.