Question: The first equation H is -6271kj/mol Using the equations 2 C6H6 (1) + 15 02 (g) - 12 CO2 (g) + 6 H20 (g) AH

The first equation H is -6271kj/mol

Using the equations 2 C6H6 (1) + 15 02 (g) - 12 CO2 (g) + 6 H20 (g) AH = 2 H2 (g) + 02 (8) - 2HO (g) AH = - 483.6 kJ/mol C(s) + 02 (g) - CO2 (8) AH - -393.5 kJ/mol Determine the molar enthalpy (in kJ/mol) for the reaction 6 C(s) + 3 H2(g) C6H6 (1)

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