Question: The first four energy levels for an atom are: E 1 = - 8 . 5 7 e V , E 2 = - 2

The first four energy levels for an atom are:
E1=-8.57eV,E2=-2.14cV,E3=-0.95eV,E4=-0.54eV
An electron with a kinetic energy of 7.74 cV collides with an atom in its ground state. After the collision, the atom is in an excited state and the electron is scattered. The kinetic energy of the scattered electron could be
16.31 eV
83 cV
0.29 cV
0.12 eV
The first four energy levels for an atom are: E 1

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