The first unit of construction is completed in 10,000 hours. A learning rate of 80 percent...

  

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The first unit of construction is completed in 10,000 hours. A learning rate of 80 percent is expected on doubled units (always assume doubled units unless specifically stated otherwise). How much time will be required to complete the eighth unit? LogL/Log2- T# 2 T# 3 T# 4 T# 5 T# 6 T# 7 T# 8 T# T# 13 T# T# 16 T# 99 N 0.85 -0.234465254 Time Req. to Produce Unit #N Using Formula#2 Using Formula#1 106250 96614.35459 90312.5 85708.8827 82122.2014 79207.05876 76765.625 68506.06186 65250.78125 42560.1256 90312.5 76765.625 65250.78125 Arithmetic approach - Uses relationship: T₂N=L* IN - Useful only if values doubled Logarithmic analysis - Uses relationship: TN = T₁ N log L / log 2 • N = Unit of interest; T₁ = Time for unit 1 - Can find time for any value of N The first unit of construction is completed in 10,000 hours. A learning rate of 80 percent is expected on doubled units (always assume doubled units unless specifically stated otherwise). How much time will be required to complete the eighth unit? LogL/Log2- T# 2 T# 3 T# 4 T# 5 T# 6 T# 7 T# 8 T# T# 13 T# T# 16 T# 99 N 0.85 -0.234465254 Time Req. to Produce Unit #N Using Formula#2 Using Formula#1 106250 96614.35459 90312.5 85708.8827 82122.2014 79207.05876 76765.625 68506.06186 65250.78125 42560.1256 90312.5 76765.625 65250.78125 Arithmetic approach - Uses relationship: T₂N=L* IN - Useful only if values doubled Logarithmic analysis - Uses relationship: TN = T₁ N log/log 2 • N = Unit of interest; T₁ = Time for unit 1 - Can find time for any value of N The first unit of construction is completed in 10,000 hours. A learning rate of 80 percent is expected on doubled units (always assume doubled units unless specifically stated otherwise). How much time will be required to complete the eighth unit? LogL/Log2- T# 2 T# 3 T# 4 T# 5 T# 6 T# 7 T# 8 T# T# 13 T# T# 16 T# 99 N 0.85 -0.234465254 Time Req. to Produce Unit #N Using Formula#2 Using Formula#1 106250 96614.35459 90312.5 85708.8827 82122.2014 79207.05876 76765.625 68506.06186 65250.78125 42560.1256 90312.5 76765.625 65250.78125 Arithmetic approach - Uses relationship: T₂N=L* IN - Useful only if values doubled Logarithmic analysis - Uses relationship: TN = T₁ N log L / log 2 • N = Unit of interest; T₁ = Time for unit 1 - Can find time for any value of N The first unit of construction is completed in 10,000 hours. A learning rate of 80 percent is expected on doubled units (always assume doubled units unless specifically stated otherwise). How much time will be required to complete the eighth unit? LogL/Log2- T# 2 T# 3 T# 4 T# 5 T# 6 T# 7 T# 8 T# T# 13 T# T# 16 T# 99 N 0.85 -0.234465254 Time Req. to Produce Unit #N Using Formula#2 Using Formula#1 106250 96614.35459 90312.5 85708.8827 82122.2014 79207.05876 76765.625 68506.06186 65250.78125 42560.1256 90312.5 76765.625 65250.78125 Arithmetic approach - Uses relationship: T₂N=L* IN - Useful only if values doubled Logarithmic analysis - Uses relationship: TN = T₁ N log/log 2 • N = Unit of interest; T₁ = Time for unit 1 - Can find time for any value of N

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