The following is a code snippet. The output to the screen will be (char*)0): pid = forko if (pid=0) execlp ("15","15", "-1", -a printf("Task completed "); 1 else if (pid > 0) wait (NULL) printf("rask completed "); Nothing will be printed to screen. a listing of files and directories in the current directory, followed by one line of 'Task completed". O a listing of files and directories in the current directory one line of "Task completed". a listing of files and directories in the current directory, followed by two lines of "Task completed". The code shown below is compiled and executed, does the thread that is created have access to the variable "flag"? typedef struct int arg1; char arg2; } args_t; int flag: void *thread_func (void *arg) { args_t *args = (args_t *) arg; /* some lines of code here not shown */ return NULL; 3 int main() { pthread_t thr; args_t args = {100, 'z'}; char *chars = malloc (1024*sizeof (char)); int nums (1024); for (int i=0; i