The force shown in Figure 7-17 moves an object from x = 0 to x = 0.75 m, where the interval between vertical dashed lines is 0.25 m. 0.8- 0.6 Force, F (N) 0.4 0.2 O Position, Figure 7-17 (a) How much work is done by the force? (b) How much work is done by the force if the object moves from x = 0.25 to x = 0.75 m?Force from, HEOnto x= 0:25m,M F1 = O.6 N 2=0: 25m to u =0:50 m, in f2= orAN n zo. 50m to 2=075my F = 018 N 1. Total Work done by the forme , Wa Hex+ Faux + fox = 016 0 125 + 014 x0 .25 + 018 x0.25 W = 0145 J 2 . Work done when the object moves 920 25mto 0, 75 m is fox= 014 x0 . 25 + 018 *0.25 2 0'3J. Work done 2 0. 35/