The forces for all members, except far member AE$,$ in the truss below were determined in class using the Method af Joints.

Check the math for the forces calculated in class for this truss, if they are needed to answer this question.

The force in kip in member AE using the Method of Joints is mostly near

$40(T)$

$32(T)$

$24(Cl)$

$32(Cl)$

$24($T$)$

$4010$

$0$