The function multiply () takes 2 parameters: x1 of type float and x2 of type float and returns the result of x1 multiplied with x2. However, upon execution, the code produces the errors as shown in the figure below. Rewrite the single line of code that will fix this bug. mainc 1 #include 2 3- int main() { 5 6 float a = 12.34, b. 15.3; 7 printf("The result of %.2f * %.2f is %.2f", a, b, multiply(a,b)); 8 9 return @; 10 } 11 12. float multiply(float x1, float x2){ 13 14 y = x1 + x2; 15 return y; 16 } 17 18 float y; input eta Compilation failed due to following error(s). main.c: In function 'main': 80. warningimpikit declaration of function multiply wheet fasti printi ("The result of 4.25 %.2f is %.2f", a, b, multiply(a,b)); 58.48kerning for at I expects argument of type "double', but argument 4 Nastyse int printf("The result of %.2f %.2f is %.2f", a, b, multiply(a,b)); main.c: At top level: error conflicting types for multiply float multiply(float xi, float x2){ main.c:8:56: note: previous implicit declaration of multiplys was here printf("The result of %.2f "%.2f is %.2f", a, b, multiply(a,b))