The function multiply takes 2 parameters; x1 of type float and x2 of type float and returns the result of xi multiplied with x2. However, upon execution, the code produces the errors as shown in the figure below. Rewrite the single line of code that will fix this bug. man 1 include 2 3. int main() { 5 6 float a = 12.34, b = 15.3; 7 printf("The result of %.2f .%.2f is %.2f", a, b, multiply(a,b)); 8 9 return 0; 10 } 11 12 - float multiply(float xi, float x2){ 13 float y; 14 y - X1 X2; 15 return y; 16 ) 17 18 stderr input Compilation failed due to following error(s) main.c: In function 'main': .:8:58: warning: implicit declaration of function 'multiply" [-kuplicit-function declaration printf("The result of %.2f %.2f is %.2f", -, b, multiply(a,b)); main.:46 warning: forsat 'X' expects argument of type "double', but argument 4 has type ant printf("The result of %.2f .%.2f is %.2f", a, b, multiply(a,b)); main.c: At top level: maits142: error: conflicting types for multiply float multiply(float x1, float x2) loc: note: previous Implicit declaration of multiply was here printf("The result of %.2f%.2f is %.2f", a, b, multiply(a,b))