Question: The graph of the quadratic function y = 2X2 4X + 1 is pictured below, along with the point P=(-1,7) on the parabola and the

 The graph of the quadratic function y = 2X2 4X +

1 is pictured below, along with the point P=(-1,7) on the parabola

The graph of the quadratic function y = 2X2 4X + 1 is pictured below, along with the point P=(-1,7) on the parabola and the tangent line through P. A line that is tangent to a parabola does not intersect the parabola at any other point. We can use this fact to find the equation of the tangent line. (a) If m is the slope of the tangent line, then using the slope/point formula, the equation of the tangent line will be: v=m(X- )+ (b) The values of x for which the point (x,y) lies on both the line and the parabola satisfy the quadratic equation: 2xZ+bx+c=0 where b: and c: (b and c should depend on m). (c) For most values of m, the quadratic equation in part (b) has two solutions or no solutions. The value of m for which the quadratic equation has exactly one solution is the slope of the tangent line. This value is m =

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