The graph of $(x-2{)}^2+(y-5{)}^2=1$ is shown on the right. Use implicit differentiation to find the slopes of the tangent lines at the points on the graph where $x=2\mathrm{.}8.$

Check your answers by visually estimating the slopes on the graph in the figure.

Using implicit differentiation, the formula for $y^{\text{'}},$ the slope of the tangent lines, is $-\frac{x-2}{y-5}.$

The slopes of the tangent lines at $x=2\mathrm{.}8$ are $-1\mathrm{.}33,1\mathrm{.}33.$

$($Use a comma to separate answers as needed. Round to the nearest hundredth as needed.$)$

Choose the graph that shows one line that looks like it is tangent at $x=2\mathrm{.}8$ and has a check point that could be used to find the slope of the line algebraically.

$$ A$.$ B$.$