The groups$\_$per$\_$user function receives a dictionary, which contains group names with the list of users. Users can belong to multiple groups. Fill in the blanks to return a dictionary with the users as keys and a list of their groups as values.

def groups$\_$per$\_$user$($group$\_$dictionary$)$ :

user$\_$groups $=\{\}$

# Go through group$\_$dictionary

for group, users in group$\_$dictionary.items$()$:

# Now go through the users in the group

for user in users:

# Now add the group to the the list of

# groups for this user, creating the entry

# in the dictionary if necessary

return$($user$\_$groups$)$

print $($groups$\_$per$\_$user$(\{"$local$"$: $["$admin$",$ "userA"$],$

"public": $["$admin$",$ "userB"$],$

"administrator": $["$admin$"]\}))$

Reset

Error on line $11$:

return$($user$\_$groups$)$

IndentationError: expected an indented block