Question: The H-P-H bind angle in phosphine (PH3) is 94.1. Determine the %S and %P character in the P-H bonds and the %S and %P character

The H-P-H bind angle in phosphine (PH3) is 94.1. Determine the %S and %P character in the P-H bonds and the %S and %P character in the orbital containing the nonbonding pair. (Hint use cos(theta)=s/(s-1).)

Really need help, I think I am overthinking it so please explain with steps. Thank you!

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