The inverse Laplace transform $L^{-1}\{\frac{s}{s^2+4s+8}\}$ equals

Select one:

$e^{-2t}(cos2t+sin2t)$

$e^{-2t}(cos2t-sin2t)$

$e^{2t}(cos2t+sin2t)$

$e^{3t}(cost-sint)$

$e^{3t}(cost+3sint)$