The midpoint Riemann sum approximation for

${\displaystyle \underset{0}{\overset{1}{}}}4x^2+3x+2dx$ for $n=5$ is

$0\mathrm{.}2[(4(0\mathrm{.}1{)}^2+3(0\mathrm{.}1)+2)+(4(0\mathrm{.}3{)}^2+3(0\mathrm{.}3)+2)+(4(0\mathrm{.}5{)}^2+3(0\mathrm{.}5)+2)+(4(0\mathrm{.}7{)}^2+3(0\mathrm{.}7)+2)+(4(0\mathrm{.}9{)}^2+3(0\mathrm{.}9)+2)]$

True

False