* The molarity of the saturated nickel (II) chloride solution is 5.210 mol/L . Since you...
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* The molarity of the saturated nickel (II) chloride solution is 5.210 mol/L . Since you made 1 L of this saturated solution, determine the mass (g) of nickel (II) chloride required to make this saturated solution (don't worry about added excess, just calculate the mass of nickel(II) chloride required to make the solution saturated. Molar mass NiCl₂ = 129.593 g/mol). Mass Required: 4 When preparing a solution of known concentration (stock solution) from the ionic solid, we must calculate the mass solid required to make the volume and concentration of solution desired. For example, if I wanted to make 1.5 L of a 0.50 M solution of sodium iodide (Nal), I would first find the number of moles of Nal required for the solution: 1.5 L (0.50 mol/L) = 0.75 mol Nal Next, I would use the molar mass of Nal to determine the mass of Nal required: 0.75 mol Nal (149.89 g/mol) = 112.4 g Nal (not worrying about sig figs) (PICTURES BELOW DO NOT REPRESENT THE SUBSTANCE OR QUANTITIES IN THE EXAMPLE). To prepare this solution, we would measure out the Nal using an analytical balance. We would carefully transfer this mass of Nal (not pictured) to a volumetric flask: FUNDAMENTAL Then you fill the volumetric flask to the mark on the neck (no more, no less). This gives you the desired final volume. 1000 ml In 20°C Based on this description, what mass (g) of potassium sulfate would be required to make 0.250 L of a 1.50 M potassium sulfate solution? * The molarity of the saturated nickel (II) chloride solution is 5.210 mol/L . Since you made 1 L of this saturated solution, determine the mass (g) of nickel (II) chloride required to make this saturated solution (don't worry about added excess, just calculate the mass of nickel(II) chloride required to make the solution saturated. Molar mass NiCl₂ = 129.593 g/mol). Mass Required: 4 When preparing a solution of known concentration (stock solution) from the ionic solid, we must calculate the mass solid required to make the volume and concentration of solution desired. For example, if I wanted to make 1.5 L of a 0.50 M solution of sodium iodide (Nal), I would first find the number of moles of Nal required for the solution: 1.5 L (0.50 mol/L) = 0.75 mol Nal Next, I would use the molar mass of Nal to determine the mass of Nal required: 0.75 mol Nal (149.89 g/mol) = 112.4 g Nal (not worrying about sig figs) (PICTURES BELOW DO NOT REPRESENT THE SUBSTANCE OR QUANTITIES IN THE EXAMPLE). To prepare this solution, we would measure out the Nal using an analytical balance. We would carefully transfer this mass of Nal (not pictured) to a volumetric flask: FUNDAMENTAL Then you fill the volumetric flask to the mark on the neck (no more, no less). This gives you the desired final volume. 1000 ml In 20°C Based on this description, what mass (g) of potassium sulfate would be required to make 0.250 L of a 1.50 M potassium sulfate solution?
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Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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