The net power flow in the +z direction for contradirectional coupling is |A||A|. Show that d...

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The net power flow in the +z direction for contradirectional coupling is |A₁|²|A₂|². Show that d ( 1A, 1² – |A₂|² )/dz = 0, where A₁ and A₂ satisfy the following coupled equations: d -A₁ = − ik A₂ (z)eißz dz d - A₂ = ik* A₁(z)e-iAßz dz The net power flow in the +z direction for contradirectional coupling is |A₁|²|A₂|². Show that d ( 1A, 1² – |A₂|² )/dz = 0, where A₁ and A₂ satisfy the following coupled equations: d -A₁ = − ik A₂ (z)eißz dz d - A₂ = ik* A₁(z)e-iAßz dz

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To show that dA2A2dz 0 we can start by taking the derivative of A2 A2 with respect to z Lets ... View the full answer