The nucleus has an extremely small size.

a$)$ The electrostatic force is therefore $\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ over nuclear distances, which are on the order of a few femtometers $().$Select an option$$increasing$$significantly decreasing$$practically constant$$

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b$)$ All protons therefore experience a repulsive force due to $\_\_\_\_\_\_\_\_\_\_\_\_\_\_.$Select an option$$all other protons$$all protons and neutrons$$only the nearest protons$$

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c$)$ The nuclear force a proton or neutron experiences is $\_\_\_\_\_\_\_\_\_\_\_\_\_\_,$Select an option$$attractive$$repulsive$$depends on whether it's a proton or neutron$$

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d$)$ and it is due to $\_\_\_\_\_\_\_\_\_\_\_\_\_\_,$Select an option$$all other protons$$all protons and neutrons$$only the nearest protons and neutrons$$

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e$)$ So in summary, the nuclear force on each nucleon $\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ mass number A $($ie$.$ number of nucleons$).$Select an option$$increases with$$decreases with$$is generally independent of$$

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f$)$ The electrostatic repulsion $\_\_\_\_\_\_\_\_\_\_\_\_\_\_$ atomic number Z $($i$.$e$.$ number of protons$)$