The number of emergency calls a fire department receives during a shift follows a Poisson distribution....

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The number of emergency calls a fire department receives during a shift follows a Poisson distribution. Suppose the mean number of calls is 3.6 for any twelve-hour period of time. What is the probability of having at least one call in a four-hour period? Hint: If you need to use a value of e^x, use one of the following: e = 0.0001 e01-0.9048 e¹2 = 0.3012 e 2=0.0407 e 23 = 0.5134 e = 0.0003 e02=0.8187 e¹50.2231 e36= 0.0273 -6 e = 0.0025 e 03 = 0.7408 e ¹6=0.2019 e³= 0.0067 e 04 = 0.6703 e¹8 = 0.1653 e =0.0183 e 05 =0.6065 e 21 = 0.1225 e³= 0.0498 e 06 =0.5488 e 24=0.0907 e08 = 0.4493 e 25= 0.0821 -0.9 e09 = 0.4066 e27 =0.0672 e²=0.1353 e¹ = 0.3679 O.6386 O.3374 O.3242 O.7783 O.9727 O.6988 e8=0.0082 e3=0.7165 -1/4 e¹4 = 0.7788 e6=0.8465 e8=0.8825 -1/9 e¹9 - 0.8948 -3/4 e³4 = 0.4724 <-5/6 e 56 =0.4346 -3/8 e 38 = 0.6873 e -5/8 = 0.5353 e -7/8 = 0.4169 e3=0.2636 -5/3 e53= 0.1889 The number of emergency calls a fire department receives during a shift follows a Poisson distribution. Suppose the mean number of calls is 3.6 for any twelve-hour period of time. What is the probability of having at least one call in a four-hour period? Hint: If you need to use a value of e^x, use one of the following: e = 0.0001 e01-0.9048 e¹2 = 0.3012 e 2=0.0407 e 23 = 0.5134 e = 0.0003 e02=0.8187 e¹50.2231 e36= 0.0273 -6 e = 0.0025 e 03 = 0.7408 e ¹6=0.2019 e³= 0.0067 e 04 = 0.6703 e¹8 = 0.1653 e =0.0183 e 05 =0.6065 e 21 = 0.1225 e³= 0.0498 e 06 =0.5488 e 24=0.0907 e08 = 0.4493 e 25= 0.0821 -0.9 e09 = 0.4066 e27 =0.0672 e²=0.1353 e¹ = 0.3679 O.6386 O.3374 O.3242 O.7783 O.9727 O.6988 e8=0.0082 e3=0.7165 -1/4 e¹4 = 0.7788 e6=0.8465 e8=0.8825 -1/9 e¹9 - 0.8948 -3/4 e³4 = 0.4724 <-5/6 e 56 =0.4346 -3/8 e 38 = 0.6873 e -5/8 = 0.5353 e -7/8 = 0.4169 e3=0.2636 -5/3 e53= 0.1889

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