The position function of a particle is given by

$s=t^3-1\mathrm{.}5t^2-282t0$

fall when does the particle reach a velocity of $8\frac{m}{s}?$

$$ s

tha when is the acceleration $0?$

$$ s

What is the significance of this value of $t?$

The acceleration changes from negative to positive, so the velocity changes from increasing to

decreasily:

The acceleration changes from positive to negative, so the velocity changes from decreasing to increasing.

The acceleration changes from positive to negotive, so the velocity changes from increasing to decreasing.

The acceleration changes from negative to positive, so the velocity changes from decreasing th increasing.