The program example below: Deadlock example. doesn$$t always lead to dead$-$lock. Describe what role the CPU scheduler plays and how it can contribute to deadlock in this program.

$/*$ thread$\_$one runs in this function $*/$

void $*$do$\_$work$\_$one$($void $*$param$)$

$\{$

pthread$\_$mutex$\_$lock$($&first$\_$mutex$)$;

pthread$\_$mutex$\_$lock$($&second$\_$mutex$)$;

$/**$

$*$ Do some work

$*/$

pthread$\_$mutex$\_$unlock$($&second$\_$mutex$)$;

pthread$\_$mutex$\_$unlock$($&first$\_$mutex$)$;

pthread$\_$exit$(0)$;

$\}$

$/*$ thread$\_$two runs in this function $*/$

void $*$do$\_$work$\_$two$($void $*$param$)$

$\{$

pthread$\_$mutex$\_$lock$($&second$\_$mutex$)$;

pthread$\_$mutex$\_$lock$($&first$\_$mutex$)$;

$/**$

$*$ Do some work

$*/$

pthread$\_$mutex$\_$unlock$($&first$\_$mutex$)$;

pthread$\_$mutex$\_$unlock$($&second$\_$mutex$)$;

pthread$\_$exit$(0)$;

$\}$