The reaction of iron (II) sulfide in the presence of oxygen produces Fe203 and S02 according...
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The reaction of iron (II) sulfide in the presence of oxygen produces Fe203 and S02 according to the following reaction: Fes + 02 Fe203 + S02 Balance the chemical equation and determine: a) How many grams of 02 will be obtained from 200 grams of S02? b) How many grams of FeS will be obtained from 345 grams of Fe203? c) How many moles of S02 will be obtained from 43 grams of 02? The reaction of iron (II) sulfide in the presence of oxygen produces Fe203 and S02 according to the following reaction: Fes + 02 Fe203 + S02 Balance the chemical equation and determine: a) How many grams of 02 will be obtained from 200 grams of S02? b) How many grams of FeS will be obtained from 345 grams of Fe203? c) How many moles of S02 will be obtained from 43 grams of 02?
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Consider the balonced reoction 4fes 702 2fe203 h502 Mole of So ot of soz 200 gm 3D 3 125 mo... View the full answer
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