The solubility product of Ag2C2O4 at 25°C is 1.29 x 10-11 mol3L-3. A solution of K2C2O4 containing 0.520 moles in 500mL water is shaken at 25°C with an excess of Ag2CO3 till the following equilibrium is reached;

Ag2CO3 + K2C2O4 ? Ag2C2O4 + K2CO3

At equilibrium, the solution contains 0.0358 moles of K2CO3. Assuming the degree of dissociation of K2C2O4 and K2CO3 to be equal, calculate the solubility product of Ag2CO3.

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