Question: The solution equation for a 1st-order, 2nd-order, and 3rd-order irreversible reaction in a constant-volume batch reactor are: 1st-order (1A>R): In = -kt 2nd-order (2A>R): =

The solution equation for a 1st-order, 2nd-order, and 3rd-order irreversible reaction in a constant-volume batch reactor are: 1st-order (1A>R): In = -kt 2nd-order (2A>R): = CA (CA) = =+ + + kt 1 1 3rd-order (3A+R): = + 2kt 2 * Assume k =1.0 (with the proper units) and C=1.0 mole/liter and t in hours. a) If C, and k the same in all three cases, for the same conversion (e.g., CA -0.50 C), what will be the reaction time needed for each of the three cases, expressed in terms of tist-order, t2nd-order/t1st-order, and t3rd-order/t1st-order? Give me the individual values and the ratios. Assume k=1.0 (with the proper units) and t =1.0 hour and Ca in mole/liter. b) If k and the reaction time, t, are the same for all three cases, to achieve the same final CA (e.g., F0.50 mole/liter), what must be the C needed for each of the three cases, expressed in terms of C Ist-order, C 2nd-order/C Ist-order and C 3rd- order/C Ist-order? Give me the individual values and the ratios
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