Question: kinetics, please solve for a like Problem 1: The solution equation for a 15-order, 2nd-order, and 3rd-order irreversible reaction in a constant-volume batch reactor are:
Problem 1: The solution equation for a 15-order, 2nd-order, and 3rd-order irreversible reaction in a constant-volume batch reactor are: 1st-order (1AR): In () =-kt - 2 + kt 2nd-order (2AR): 3rd-order (3A+R): +2kt Assume k =1 (with the proper units) and CX=1 mole/liter and t in hours. a) If C and k the same in all three cases, for the same conversion (e.g., CA=0.5C), what will be the reaction time needed for each of the three cases, expressed in terms of tist-order, tznd-order/tist-order, and t3rd-order/t1st-order? Assume k =1 (with the proper units) and t= 1 hour and CA in mole/liter. b) If k and the reaction time, t, are the same for all three cases, to achieve the same final CA (e.g., 0.5 mole/liter), what must be the C needed for each of the three cases, expressed in terms of C Ist-order, C 2nd-orded C Ist-order and Ca sird. order/ C 1st-order
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