The solution for a pendulum oscillation is: e(t) = 2a cos(wt) - 2b.sin(wt) whereas is the...

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The solution for a pendulum oscillation is: e(t) = 2a cos(wt) - 2b.sin(wt) whereas is the angle at time t and w is the angular frequency. Show that this solution can also be expressed in the following form: e(t)o cos(wt - a) whereas Ao is the deflection angle and a is the initial phase angle. Hint: Use the Euler formula: exp(ix) = cos(p) + i sin(p) . Mg sine Mg (1) (2) (3) The solution for a pendulum oscillation is: e(t) = 2a cos(wt) - 2b sin(wt) whereas is the angle at time t and w is the angular frequency. Show that this solution can also be expressed in the following form: e(t)o cos(wt - a) whereas eo is the deflection angle and a is the initial phase angle. Hint: Use the Euler formula: exp(ix) = cos(p) + i sin(p) . Mg sine Mg (1) (2) (3) The solution for a pendulum oscillation is: e(t) = 2a cos(wt) - 2b.sin(wt) whereas is the angle at time t and w is the angular frequency. Show that this solution can also be expressed in the following form: e(t)o cos(wt - a) whereas Ao is the deflection angle and a is the initial phase angle. Hint: Use the Euler formula: exp(ix) = cos(p) + i sin(p) . Mg sine Mg (1) (2) (3) The solution for a pendulum oscillation is: e(t) = 2a cos(wt) - 2b sin(wt) whereas is the angle at time t and w is the angular frequency. Show that this solution can also be expressed in the following form: e(t)o cos(wt - a) whereas eo is the deflection angle and a is the initial phase angle. Hint: Use the Euler formula: exp(ix) = cos(p) + i sin(p) . Mg sine Mg (1) (2) (3)

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Solution Eulers formula states that ei cosisin Where e is the base of the natural logarithm i is the ... View the full answer