Question: The solution to dy = 2 e**y with initial condition (0, -In 5) can be expressed as y = -In (j - ke) for

The solution to dy = 2 e**y with initial condition (0, -In 5) can be expressed as y = -In (j - ke) for real numbers j dx and k. What are the values of j 

The solution to dy = 2 e**y with initial condition (0, -In 5) can be expressed as y = -In (j - ke) for real numbers j dx and k. What are the values of j and k? If = dx - siny, then the solution passing through point (,) is There are initially 1,000 bacteria in a colony. The rate at which the number of bacteria in the colony changes is dN given by dit -=kN, where k is a constant. If the number of bacteria doubles every 21 minutes, which function models the number of bacteria, N(t), after t minutes?

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To find the values of j and k in the equation y lnj k e2x we can use the initial condition 0 ln5 Sub... View full answer

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