Question: The solution to the Initial value problem 1 + 2 + 502 = 4 cos(5t), z(0) = 0, z'(0) = 0 is the sum of

The solution to the Initial value problem 1 + 2 + 502 = 4 cos(5t), z(0) = 0, z'(0) = 0 is the sum of the steady periodic solution , and the transient solution . Find both Isp and Itr. I sp = cos( 7t) + 205 sin( 7t) It = -40 25 + 50e -251

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