Question: The stabilized hysteresis loop for a material under cyclic loading is determined to have the following values: Strain amplitude ( 2 ) = 0 .

The stabilized hysteresis loop for a material under cyclic loading is determined to have the following values:
Strain amplitude (2)=0.002
Mean stress (m)=-9.5ksi
Maximum stress (max)=30.5ksi
The strain-life parameters for the material are E=30103ksi,f'=133ksi,b=-0.095,f'=0.26, and c=-0.47. Determine the cycles to failure, Nf, using each of the following three relationships that can be used to account for the mean stress effect on life:
(1) Morrow: 2=f'-mE(2Nf)b+f'(2Nf)c
(2) Manson-Halford: 2=f'-mE(2Nf)b+f'(f'-mf')cb(2Nf)c
(3) Smith-Watson-Topper (SWT): max2=(f')2E(2Nf)2b+f'f'(2Nf)b+c
Q2.
given below are the cyclic stress-strain and strain-life parameters for a steel:
E=30103ksi,H'=174.6ksi,n'=0.202,f'=133ksi,b=-0.095,f'=0.26, and c=-0.47
Determine the life of this material under the following strain histories. History A is constant amplitude, while histories B and C have initial overloads which set up residual stresses. Use the Morrow, Manson-Halford, and SWT relationships for these calculations. Compare the predictions made using the three methods.
The stabilized hysteresis loop for a material

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