Question: The TCP in station A sends a SYN segment with ISN (Initial Sequence Number) = 1000 to Station B. Station B replies with a SYN
The TCP in station A sends a SYN segment with ISN (Initial Sequence Number) = 1000 to Station B. Station B replies with a SYN segment with ISN = 5000 and MSS (Maximum Segment Size) = 500. Suppose station A has 10,000 bytes to transfer to B. Assume the link between stations A and B is 8 Mbps and tprop=1 microsecond. Neglect the header overheads to keep the arithmetic simple. Station B has 3000 bytes of buffer available to receive data from A. Sketch the sequence of segment exchanges, including the parameter values in the segment headers, and the state as a function of time at the two stations under the following situations (assume that the send window is replenished by the receiver a soon as it receives a segment):
(a) Station A sends its first data segment at t = 0. Station B has no data to send and sends an ACK (Acknowledgment) segment every other frame.(Explain with diagram)
(b) Station A sends its first data segment at t = 0. Station B has 6000 bytes to send, and it sends its first data segment at t = 2 ms.(Explain with diagram)
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
