The titration technique is used to do the reaction because the 0.1 M NaOH can be added sequentially and the pH is monitored as the moles of HA react to form NaA. The Ka is calculated at the three lettered points. Use the information is question 1 to find:

(a) How many moles of HA are present at point A (initial)?

(b) How many moles of HA are present at point B (the half-equivalence point)?

(c) How many moles of HA are present at point C (the equivalence point)?

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10 pH 5 To 15 to a5 30 mi vol. NaOH 1164T3 10 pH 5 To 15 to a5 30 mi vol. NaOH 1164T3