Question: The torque T exerted by an engine at any crank angle 6 is given by the expression: T 7500+3000sinG - 1500sin20 + 600sin30 Nm

The torque T exerted by an engine at any crank angle 6 is given by the expression: T 7500+3000sinG - 1500sin20 + 600sin30 Nm The engine works against a uniform resistance, at a mean speed of 160 rpm. The flywheel has a mass of 1.2 t and a radius of gyration of I m. Calculate: ) The power of the engine (ii) The coefficient of fluctuation of speed

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SOLUTION i To calculate the power of the engine we need to calculate the torque arm of the flywheel which is the distance from the axis of rotation to ... View full answer

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